Two straight lines: 2x-3y-3=0 and x+y+2=0, just solve for the x and y values.

x+y+2=0 =>y=-x-2 Substitute 2x-3y-3=0 and we get =>2x+3x+6-3=0 =>x=-3/5 =>y=3/5-2=-7/5

So the intersection of the two lines is (-3/5, -7/5)